Saturday, November 12, 2011
I have a math problem I need help with?
Okay, first the runner is going 3 times as fast as the walker. That means, when the runner goes .75 miles, the walker would have gone only .25 miles. Those two distances are a mile, combined, so they will meet when the walker has gone .25 miles. Now, if that walker was to walk for a full hour, it would have gone 3 miles. If you were to look at how many .25 mile segments are in 3 miles, you would have 12 segments. Now, to translate that into time, look at how much a 12th of an hours is. A 12th of an hour is 5 minutes. So, they will meet in 5 minutes, when the walker has gone a quarter mile, and the runner had gone 3 quarters of a mile. Not exactly a traditional math problem, from my solution...but i am right.:P
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